`(n)C_(8)=^(n)C_(2),`" find `n C_(2)`

If .^(n)C_(9)=.^(n)C_(7) , find n.

If .^(n)C_(8)=.^(n)C_(6) , then find .^(n)C_(2) .

if .^(2n)C_(2):^(n)C_(2)=9:2 and .^(n)C_(r)=10 , then r is equal to

If .^(n)C_(12) = .^(n)C_(16) , find the value of n

If .^(n)C_(5) = .^(n)C_(7) , then find .^(n)P_(3)

If ""^(n)C_(10)=""^(n)C_(13) , then find the value of ""^(n)C_(2)

The A.M. of the series .^(n)C_(0), .^(n)C_(1), .^(n)C_(2),….,.^(n)C_(n) is

The arithmetic mean of ""^(n)C_(0),""^(n)C_(1),""^(n)C_(2), ..., ""^(n)C_(n) , is

If .^(2n)C_(3):^(n)C_(3)=11:1 , find the value of n.

Find the value of n: (i) .^(n)C_(10)=^(n)C_(16) (ii) .^(15)C_(n) =^(15)C_(n+3) (iii) .^(10)C_(n) =^(10)C_(n+2) (iv) .^(25)C_(3n) =.^(25)C_(n+1) (v) .^(n)C_(r) =.^(n)C_(r-2)