If y=y(x) is the solution curve of the differential equation x^2 dy +(y-1/x )dx =0 ; x>0 and y(1)=1, then y(1/2) is equal to

If y = y(x) is the solution of the differential equation, x dy/dx+2y=x^2 satisfying y(1) = 1, then y(1/2) is equal to

If for x ge 0, y = (x) is the solution of the differential equation, (x+1)dy=((x+1)^2+y-3)dx,y(2)=0 , then y(3) is equal to ….

Let y(x) is the solution of the differential equation (x+2)(dy)/(dx)-(x+1)y=2 . If y(0)=-1 , then the value of y(2) is equal to

Solution of the differential equation (1+x)y dx+(1-y)x dy=0 is

Solve the differential equation x^2dy+(x y+y^2)dx=0 given y=1, when x=1

Verify that y=-x-1 is a solution of the differential equation (y-x)dy-(y^2-x^2)dx=0.

If y = y(x) is the solution of the differential equation, x (dy)/(dx) + 5y = 10x^5, x > 0 satisfying y(1) = 2 then range of y(x) for x > 0 is:

If y(x) is the solution of the differential equation (dy)/(dx)=-2x(y-1) with y(0)=1 , then lim_(xrarroo)y(x) equals

If y(x) is the solution of the differential equation (dy)/(dx)=-2x(y-1) with y(0)=1 , then lim_(xrarroo)y(x) equals

The solution of the differential equation x(dy)/(dx) + 2y = x^2 (X ne 0) with y(1) =1, is :