Find the % error in heat loss if error in current is `2%` resistance `1%` and time `1%` (Given `H=I^(2)Rt` )

Find : 1% of Rs 325

The heat generated in a circuit is given by Q = I^(2) Rt , where I is current , R is resistance , and t is time . If the percentage errors in measuring I , R , and t are 2% , 1% , and 1% , respectively , then the maximum error in measuring heat will be

A physical quantity Q is related to measurable quantities L,M and N as Q = KL^(-2)M^(2)N^(3) , where k is constant. If the % errors in the measurements of L, M and N are respectively 1%, 2% and 1%, then the % error in hc mcasurement of Q is

In the experiment of verification of Ohm's law the error in the current measurement is 1%, while that in the voltage measurement is 2%. The error in the resistance has a maximum value of

The heat produced in a long wire is characterised by resistance , current and time through which the current passes. If the errors in measuring these quantities are respectively 2%, 2% and 2% then total error in calculating the energy produced is

What is the maximum percentage error in density of body if percentage error in measurement of mass is 4% , and percentage error in measurement of side 1% ?

The time period (T) of small oscillations of the surface of a liquid drop depends on its surface tension (s), the density (rho) of the liquid and it's mean radius (r) as T = cs^(x) p^(y)r^(z) . If in the measurement of the mean radius of the drop, the error is 2 % , the error in the measurement of surface tension and density both are of 1% . Find the percentage error in measurement of the time period.

The heat generated in a circuit is dependent upon the resistance, current and time for which the current is flown. If the error in measuring the above are 1%, 2% and 1% respectively, then maximum error in measuring the heat is

According to Joule's law of heating , heat produced H = I^(2) Rt , where I is current , R is resistance of I , R , and t are 3% , 4% , and 6% , respectively , find error in the measurement of H .

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.