Starting from rest,the cable can be wound onto the drum of the motor at a rate of `V_(A)` = `(3t^(2))`m/s where "t" is in seconds.If the time needed to lift the load `7m` is `8n^(1/3)` sec.Find the value of "n"

If v=(t^(2)-4t+10^(5)) m/s where t is in second. Find acceleration at t=1 sec.

The velocity of a particle is given by v=(4t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=1 second.

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.

Blocks P and R starts from rest and moves to the right with acceleration a_(p) = 12t m//s^(2) and a_(R) = 3 m//s^(2) . Here t is in seconds . The time when block Q again comes to rest is

A particle is acted upon by a force given by F=(12t-3t^(2)) N, where is in seconds. Find the change in momenum of that particle from t=1 to t=3 sec.

Force applied on a body is given by ltbygt F=(3t^(2)-2t+10) N where t is in seconds. Find impulse imparted in t=0 to t=2 sec.

The voltage supplied to a circuit is given by V=V_(0)t^(3/2) , where t is time in second. Find the rms value of voltage for the period, t=0 to t=1s.

A particle moves clockwise in a circle of radius 1 m with centre at (x, y) = (1m, 0) . It starts from rest at the origin at time t = 0 . Its speed increase at the constant rate of ((pi)/(2)) m//s^(2) . If the net acceleration at t = 2 sec is (pi)/(2) sqrt((1 + Npi^(2)) then what is the value of N ?

A particle of mass 1 kg moves in a circular path of radius 1 m such that its speed varies with time as per equation v=3t^(2)m//s where time t is in seconds. The power delivered by the force acting on the paritcle at t=1s , is :-

A particle moves in a circle of radius 1 cm at a speed given v = 2t , where v is cm/s and t is in seconds. Total acceleration of the particle at t=1 second is 2 sqrt(n) cm//s^(2) . Find value of n .