`cos((3 pi)/(2)+x)cos(2 pi+x)[cot((3 pi)/(2)-x)+cot(2 pi+x)]`=1

Prove that: cos((3pi)/2+x)cos(2pi+x)[cot((3pi)/2-x)+cot(2pi+x)]=1

Prove that: cos((3pi)/2+x)cos(2pi+x){cot((3pi)/2-x)+"cot"(2pi+x)}=1

The value of "cos"((3pi)/2+x)."cos"(2pi+x)["cot"((3pi)/(2)-x)+"cot"(2pi+x)] is

(cos (pi+x).cos(-x))/(sin(pi-x).cos(pi/2+x)) = cot^2x

The expression (tan(x-(pi)/(2)).cos((3pi)/(2)+x)-sin^(3)((7pi)/(2)-x))/(cos(x-(pi)/(2)).tan((3pi)/(2)+x)) simplifies to

(cos(pi-x)cos(-x))/(sin(pi-x)cos(pi/2+x))=cot^(2)x

Show that cot(pi/4+x)cot(pi/4-x)=1

lim_(xrarrpi//2)(cos((pi)/(2)sin^(2)x))/(cot((pi)/(2)sin^(2)x)) equals

The solution set of the equation ("sin" 13^(@))^("cot" 3x+ "cot"x) = "sin"^(2) (4pi-x)-"cos" (3pi-x) "cos" (2 pi +x) is given by

Prove that: cos((3pi)/4+x)-cos((3pi)/4-x)=-sqrt(2)sinx