`tan^-1(sinx/(1+cosx))`

The derivative of tan^(-1) ((sinx -cosx)/(sinx +cosx)) , with respect to (x)/(2) , where x in(0,(pi)/(2)) is:

Find the value of tan^-1((sinx+cosx)/(cosx-sinx))

If y=tan^(-1)((sinx+cosx)/(cosx-sinx)) , then (dy)/(dx) is equal to (a) 1/2 (b) 0 (c) 1 (d) none of these

The function f(x)=tan^(-1)(sinx+cosx) is an increasing function in

Prove that tan^-1((cosx)/(1+sinx))=pi/4-x/2,\ x in (-pi/2,pi/2)

Show that f(x)=tan^(-1)(sinx+cosx) is decreasing function on the interval (pi/4,pi/2)dot

Show that f(x)=tan^(-1)(sinx+cosx) is an increasing function on the interval (0,\ pi//4) .

Show that f(x)=tan^(-1)(sinx+cosx) is a decreasing function on the interval on (pi//4,\ pi//2) .

Integrate the functions (sinx)/(1+cosx)

tan^-1((1+cosx)/(sinx))