`dy/dx=(1+x^2)/(1+y^2)`

Solve: (dy)/(dx)=(1+y^2)/(1+x^2)

Solve the following differential equations. (dy)/(dx )=(1+y^2)/(1+x^2) if y=1 for x=0

If y= "tan"^(-1) (2x)/(1-x^(2)) , prove that (dy)/(dx)= (2)/(1 + x^(2))

Solve the following differential equations (dy)/(dx)*xy^(2)(1+x^(2))+(1+y^(3))=0

The family of curves represented by (dy)/(dx)=(x^(2)+x+1)/(y^(2)+y+1) and the family represented by (dy)/(dx)+(y^(2)+y+1)/(x^(2)+x+1)=0

Solve the initial value problem: y-x(dy)/(dx)=2(1+x^2(dy)/(dx)),\ y(1)=1

The solution of (dy)/(dx)=(x^2+y^2+1)/(2x y) satisfying y(1)=1 is given by

The solution of (dy)/(dx)=(x^2+y^2+1)/(2x y) satisfying y(1)=1 is given by

The solution of the differential equation x=1+x y(dy)/(dx)+(x^2y^2)/(2!)((dy)/dx)^2+(x^3y^3)/(3!)((dy)/(dx))^3+... i s

If (dy)/dx = (xy)/(x^2 + y^2), y(1) = 1 and y(x) = e then x =