A disc rolls down without slipping. From rest on 37 inclined.its linear acceleration is ​

STATEMENT-1 : Two disks having same radius but different masses roll down without slipping from rest, on a rough inclined plane. They will take the same time to reach the bottom. and STATEMENT-2 : The heavier disc will have greater kinetic energy than the lighter disc, at the bottom.

A solid uniform disc of mass m rolls without slipping down a fixed inclined plank with an acceleration a. The frictional force on the disc due to surface of the plane is

Consider a uniform disc of mass m , radius r rolling without slipping on a rough surface with linear acceleration a and angular acceleration alpha due to an external force F as shown in the figure coefficient of friction is mu . Q. The magnitude of frictional force acting on the disc is

Consider a uniform disc of mass m , radius r rolling without slipping on a rough surface with linear acceleration a and angular acceleration alpha due to an external force F as shown in the figure coefficient of friction is mu . Q. Angular momentum of the disc will be conserved about

Consider a uniform disc of mass m , radius r rolling without slipping on a rough surface with linear acceleration a and angular acceleration alpha due to an external force F as shown in the figure coefficient of friction is mu . Q. The work done by the frictional force at the instant of pure rolling is

When a point mass slips down a smooth incline from top, it reaches the bottom with linear speed v. If same mass in the form of disc rolls down without slipping a rough incline of identical geometry through same distance, what will be its linear velocity at the bottom ?

A solid uniform disc of mass m rols without slipping down a fixed inclined plank with an acceleration a. The frictional force on the disc due to surface of the plane is

An inclined plane makes an angle of 60^(@) with horizontal. A disc rolling down this inclined plane without slipping has a linear acceleration equal to

A small disc is released from rest at A on an inclined plane AB so that it rolls down without slipping. It reaches the bottom with linear velocity v_(1) in time t_(1) . Next a small ring released form rest on the inclined plane AC so that it rolls down without slipping. It reaches the bottom with linear vlocity v_(2) in time t_(2) . Given theta_(1)=30^(@), theta_(2)=60^(@), and h=10m. Then,

A solid sphere of mass m rolls without slipping on an inclined plane of inclination theta . The linear acceleration of the sphere is