A radioactive sample of decay constant `lambda` starts decaying at time t=0 .The instant of time at which probability of survival of a nucleus is twice the probability of it having decayed is

The decay constant (lambda) for radioactive decay is independent of

The probability of nucleus to decay in two mean lives is

Two radioactive materials have decay constant 5lambda&lambda . If initially they have same no. of nuclei. Find time when ratio of nuclei become ((1)/(e))^(2) :

Two radioactive materials have decay constant 5lambda&lambda . If initially they have same no. of nuclei. Find time when ratio of nuclei become ((1)/(e))^(2) :

A radioactive element A of decay constant lamda_(A) decays into another radioactive element B of decay constant lamda_(B) . Initially the number of active nuclei of A was N_(0) and B was absent in the sample. The maximum number of active nuclei of B is found at t=2. In 2//lamda_(A) . The maximum number of active nuclei of B is

A certain radioactive substance has a half life of 5 years. Thus for a nucleus in a sample of the element, probability of decay in 10 years is

A sample contains large number of nuclei. The probability that a nucleus in sample will decay after four half lives is

A sample contains large number of nuclei. The probability that a nucleus in sample will decay after four half lives is

A radioactive nucleus can decay be either emitting an alpha particle or by emitting a beta particle. Probability of alpha decay is 75% while that of beta decay is 25% the decayconstatnt of alpha decay is lamda_(1) and that of beta decay is lamda_(2) is (lamda_(1))/(lamda_(2))

Decay constant of two radioactive samples is lambda and 3lambda respectively. At t = 0 they have equal number of active nuclei. Calculate when will be the ratio of active nuclei becomes e : 1 .