The series `[CoCl_(n)(NH_(3))_(6-0)]Cl_(3-4)` given rise to `4,3,2` and zero ions in solution respectively, for `n=0,1,2` and `3`. For which value of `n`, the complex will show minimum freezing point depression?

The number of ions given by [Pt(NH_(3))_(6)]Cl_(4) in aqueous solution will be

In solution, the complex, [Pt(NH_3)_6]Cl_4 gives

[CoCl_(2)(NH_(3))_(4)]^(+)+Cl^(-) to [CoCl_(3)(NH_(3))_(3)]+NH_(3) . If in this reaction two isomers of the produt are obtained, which is true for the iniital (reactant) complex:

[CoCl_(2)(NH_(3))_(4)]^(+)+Cl^(-) to [CoCl_(3)(NH_(3))_(3)]+NH_(3) . If in this reaction two isomers of the produt are obtained, which is true for the iniital (reactant) complex:

In the reaction [CoCl_(2)(NH_(3))_(4)]^(o+)rarr[CoCl_(3)(NH_(3))_(3)]+NH_(3) , only one isomer of the complex product is obtained. Is the initial complex cis or trans ? .

The equation x^(3)+3x^(2)+6x+3-2cosx=0 has n solution(s) in (0, 1), then the value of (n+2) is equal to

Given the molecular formula of the hexacoordinated complexes (A) [CoCl_(3).6NH_3] (B) [CoCl_(3).5NH_3] (C) CoCl_(3).4NH_3 . If the number of coordinated NH_3 molecules in A, B and C respectively are 6, 5 and 4, the primary valency in (A), (B) and (C) are:

An octahedral complex is prepared by mixing CoCl3 and NH3 in the molar ratio 1 : 4, 0.1 m solution of this complex was found to freeze at 0.372°C. What is the formula of the complex? Given that molal depression constant (Kf) for water = 1.86°C/m.

Each of the compounmds Pt(NH_(3))_(6)Cl_(4), Cr(NH_(3))_(6)Cl_(3) and K_(2)PtCl_(6)Co(NH_(3))_(4)Cl_(3) were dissolved in water to make its 0.01 M solution. The correct order of their increasing conductivity in solution is

A 0.01 m.complex of CoCl_(3) and NH_(3) (molar ratio 1:4) is found to give freezing point of - 0.0372. Suggest the formula of the complex