Home
Class 12
PHYSICS
A radiation is emitted by 1000W bulb and...

A radiation is emitted by `1000W` bulb and it generates an electric field and magnetic field at P, placed at a distance of 2m. The efficiency of the bulb is `1.25%`.The value of peak electric field at P is `x times10^(-1)``V`/`m`. Value of "x" is ______ . (Rounded-off to the nearest integer) [Take `varepsilon_(0)` = `8.85times10^(-12)``C^(2)``N^(-1)``m^(-2)`,c = `3times10^(8)``ms^(-1)`

Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the electric and magnetic fields produced by the radiation coming from a 100 W bulb at a distance of 3 m . Assume that the efficiency of the bulb is 25% and it is a point source.

Calculate the electric and magnetic fields produced by the radiation coming from a 100 W bulb at a distance of 3 m . Assume that the efficiency of the bulb is 25% and it is a point source.

A charged particle with a velocity 2xx10^(3) ms^(-1) passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is 1.5 T. the magnitude of electric field will be

An electromagnetic wave is radiated by a 100 W bulb. If efficiency of the bulb is 20% then the amplitude of magnetic field at a distance of 1 m is (consider bulb as a point source)

Manitude of the electric and magnetic field in an electromagnetic wave radiated by a 200 W bulb at a distance 2m from it is assuming efficiency of bulb is 5% and it behaves like a point source.

Manitude of the electric and magnetic field in an electromagnetic wave radiated by a 200 W bulb at a distance 2m from it is assuming efficiency of bulb is 5% and it behaves like a point source.

A laser beam has intensity 2.5 xx 10^14W m^-2 . Find the amplitudes of electric and magnetic fields in the beam.

A laser beam has intensity 2.5 x (10^14)W (m^-2) . Find the amplitudes of electric and magnetic fields in the beam.

The electric field due to a charge at a distance of 3 m from it is 500 NC^(-1) . The magnitude of the charge is [(1)/(4 pi epsi_(0)) = 9 xx 10^(9) N - m^(2)//C^(2)]

The force experienced by a charge of 2mu C in an electric field is 3 xx 10^(-3)N . The intensity of the electric field.