`xy^(2)dx+(y+1)e^(-x)dy=0`

(3xy+y^(2))dx+(x^(2)+xy)dy=0

Solution of the differential equation (xy+y+e^(-x))dx+(x+e^(-x))dy=0 when y(0)=1 Then y(-1)= is equal to (A)(e)/(e-1)(B)(2e)/(e-1)(C)(e)/(1-e)(D)0

(y^(2)-xy)dx+x^(2)dy=0

y(2xy+e^(x))^(x)dx-e^(x)dy=0

The solution of x^(2)dy-y^(2)dx+xy^(2)(x-y)dy=0, is

y^(2) dx + (xy + x^(2) )dy = 0

Find the particular solution of the differential equation (3xy+y^(2))dx+(x^(2)=xy)dy=0;f or x=1,y=1

(x^(3)+xy^(4))dx+2y^(3)dy=0

Solve (1+2e^(x/y))dx+2e^(x/y)(1-x/y)dy=0