Calculate the value of the force from the following data.`G=6.67times10^(-11)` N.`m^(2)/(kg^(2))` ,`m_(1)`=40kg,`m_(2)`=20kg,r=20m

Assuming the earth b to be a homogeneous sphere determine the density of the earth from the following data. g = 9.8 m//s^(2), G = 6.67 xx 10^(-11) Nm^(2) kg^(2) , radius of the earth = 6372km.

The force with which the erth attracts an object is called the weight of the object. Calculate the weight of the moon from the following data: The universal constant of gravitastion G=6.67xx10^-11 N-m^2/kg^2 mass of the moon =7.36xx10^22 kg, mass of the earth =6xx10^24 kg and the distasnce between the earth and the moon=3.8xx10^5 km.

Three masses of 1kg , 2kg , and 3kg , are placed at the vertices of an equilateral triangle of side 1m . Find the gravitational potential energy of this system. Take G= 6.67xx10^(-11) N-m^(2)//kg^(2) .

The mass of the earth is 6 × 10^(24) kg and that of the moon is 7.4 xx 10^(22) kg. If the distance between the earth and the moon is 3.84xx10^(5) km, calculate the force exerted by the earth on the moon. (Take G = 6.7 xx 10^(–11) N m^(2) kg^(-2) )

Three masses of 1 kg, 2kg, and 3 kg are placed at the vertices of an equilateral triangle of side 1m. Find the gravitational potential energy of this system (Take, G = 6.67 xx 10^(-11) "N-m"^(-2)kg^(-2) )

If the acceleration due to gravity on earth is 9.81 m//s^(2) and the radius of the earth is 6370 km find the mass of the earth ? (G = 6.67 xx 10^(-11) Nm^(2)//kg^(2))

Two masses 800 kg and 600kg are at a distance 0.25 m apart. Calculate the magnitude of the gravitational intensity at a point distant 0.20 m from the 800 kg and 0.15 m from the 600 kg mass. G = 6.66 xx 10^(-11) Nm^(2) kg^(-2) .

Find the speed of both the blocks at the moment the block m_(2) hits the wall AB, after the blocks are released from rest. Given that m_(1) =0.5 kg and m_(2) =2 kg, (g=10 m//s^(2)) .

The gravitational force between two identical objects at a separation of 1m is 0.0667 xx 10^(-6). Find the mass of each object ( G = 6.67 xx 10^(-11) Nm^(2)//kg^(2) and g = 10m//s^(2) )

If in a system the force of attraction between two point masses of 1kg each situated 1km apart is taken as a unit force and is called notwen (newton written in reverse order) If G = 6.67 xx 10^(-11) N-m^(2)kg^(-2) in \SI units, the relation of newton and nowton is