A body makes shm on a line of length 20 cm . velocity at mean position is twice the acceleration at extreme position. what will be the displacement from mean position after time 1.57 second

A body is vibrating in simple harmonic motion . If its acceleration in 12 cms^(-2) at a displacement 3 cm from the mean position, then time period is

For Question , find maximum velocity and maximum acceleration Hint : Maximum velocity = Aomega Maximum acceleration = A omega^(2) A particle executes SHM on a straight line path. The amplitude of oscillation is 3cm . magnitude of its acceleration is equal to that of its velocity when its displacement from the mean position is 1cm.

A particle executes SHM on a straight line path. The amplitude of oscialltion is 3 cm. Magnitude of its acceleration is eqal to that of its velocity when its displacement from the mean position is 1 cm. Find the time period of S.H.M. Hint : A= 3cm When x=1 cm , magnitude of velocity = magnitude of acceleration i.e., omega(A^(2) - x^(2))((1)/(2)) = omega^(2) x Find omega T = ( 2pi)(omega)

The particle is executing SHM on a line 4 cm long. If its velocity at mean position is 12 m/s , then determine its frequency.

The figure shows a graph between velocity and displacement (from mean position) of a particle performing SHM :

Which of the following quantities is always negative is SHM ? Here, x is displacement , from mean position.

Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be

A ball attached to one end of a string swings in a vertical plane such that its acceleration at point A (extreme position) is equal to its acceleration at point B (mean position), The angle theta is

Two particles P_(1) and P_(2) are performing SHM along the same line about the same mean position , initial they are at their extreme position. If the time period of each particle is 12 sec and the difference of their amplitude is 12 cm then find the minimum time after which the separation between the particle becomes 6 cm .

Two particles undergo SHM along parallel lines with the same time period (T) and equal amplitudes. At particular instant, one particle is at its extreme position while the other is at its mean position. The move in the same direction. They will cross each other after a further time.