An electric dipole having dipole Moment `(4times10^(-9))` `C`-`m` is placed at origin along `x`-axis. What uniform electric field (in `N/m`) should be applied along `x`-axis so that we get a equipotential spherical surface of radius `3m` centred at origin?

An electric dipole is placed at origin in the xy plane with its orientation along the positive x-axis. The direction is electric field .

An electrtic dipole with dipole moment 4xx10^(-9) C m is aligned at 30^(@) with the direction of a uniform electric field of magnitude 5xx10^(4) NC^(-1) . Calculate the magnitude of the torque acting on the dipole .

A dipole of Dipole moment vec(p)=(p_(0))/(sqrt(2))(hat(i)+hat(j)) . Is placed at origin. Now a uniform external electrical filed at magnitude E_(0) is applied along direction of dipole. Two points A and B are lying on a equipotential surface of radius R centered at origin. A is along axial position of dipole and B is along equatorial position. There correct option are :

An electric dipole of diople moment 20xx10^(-6)C m is enclosed by a closed surface. What is the net electric flux coming out of the surface ?

A charge q = -2.0 muC is placed at origin. Find the electric field at (3 m, 4 m, 0) .

An electric dipole is placed along x -axis with its centre at origin:

A short electric dipole having dipole moment overline rho is placed along x-axis as shown in figure. The electric potential at point A(-2, 3) is ( k=1/4π epsilon_0 and all quantities are in S. I. units)

A dipole of magnetic moment vec(m)=30hatjA m^(2) is placed along the y-axis in a uniform magnetic field vec(B)= (2hat i +5hatj)T . The torque acting on it is

A dipole of dipole moment vecp=phati lies along the x -axis in a non-uniform electric field vecE=(c)/(x)hati . The force acting on the dipole is

An electric dipole of dipole moment p = 6 * 10^-4 C m is placed in a uniform external electric field of intensity 2*10^5(N/C) as shown in the figure, The anglebetween net electric field with external electric field at point A will be (epsilon