A cosmic body is headed directly towards earth with a speed of 10km/ sec relative to earth when it is 20 times the radius of earth from its center.What is the speed of cosmic body when it reaches earth's surface? Mass of earth =`5.98times10^(24)kg`

A body at rest starts from a point at a distance r (gtR) from the centre of the Earth. If M and R stand for the speed of the body when it reaches the Earth surface is

The mass of Mars is ( 1//9) times that of the earth and its radius is ( 1//2) that of the earth. What is the weight of a body having a mass of 100kg on the surface of the earth?

A particle falls on earth : (i) from infinity. (ii) from a height 10 times the radius of earth. The ratio of the velocities gained on reaching at the earth's surface is :

A body of mass m is lifted up from the surface of earth to a height three times the radius of the earth R . The change in potential energy of the body is

An asteroid is moving directly towards the centre of the earth. When at a distance of 4R (R is the radius of the earth) from the earths centre, it has a speed of 2sqrt2 km/s. Neglecting the effect of earths atmosphere, what will be the speed of the asteroid when it hits the surface of the earth (escape velocity from the earth is 11.2 km/s)? Give your answer to the nearest integer in kilometer/s _________.

An asteroid is moving directly towards the centre of the earth. When at a distance of 4R (R is the radius of the earth) from the earths centre, it has a speed of 2sqrt2 km/s. Neglecting the effect of earths atmosphere, what will be the speed of the asteroid when it hits the surface of the earth (escape velocity from the earth is 11.2 km/s)? Give your answer to the nearest integer in kilometer/s _________.

Calculate the orbital speed of the Hubble space telescope orbiting at a height of 598 km above the earth's surface. Take R = 6400km. Mass of earth - 5.98 xx 10^(24) kg

The escape speed of a body on the earth's surface is 11.2kms^(-1) . A body is projected with thrice of this speed. The speed of the body when it escape the gravitational pull of earth is

The weight of a body on the surface of the earth is 12.6 N. When it is raised to height half the radius of earth its weight will be

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .