When `0.2g` of acetic acid is added to `20g` of benzene, its freezing point decreases by `0.45^(@)C`. If % dimerisation of acetic acid in benzene is `X%`. Find value of `((X)/(10))`
`K_(f)` (Benzene) `=5K-kgmol^(-1)`

The freezing point of benzene decreases by 0.45^(@)C when 0.2 g of acetic acid is added to 20 g of benzene. IF acetic acid associates to form a dimer in benzene, percentage association of acetic acid in benzene will be (K_(f) "for benzene" = 5.12 K kg mol^(-1))

When 0.4 g of acetic acid is dissolved in 40 g of benzene, the freezing point of the solution is lowered by 0.45 K. Calculate the degree of association of acetic acid. Acetic acid forms dimer when dissolved in benzene. ( K_(f) for benzene = 5.12 K kg mol^(-1) at.wt. C = 12, H = 1, O = 16)

The freezing point of solution containing 0.2 g of acetic acid in 20.0 g of benzene is lowered by 0.45^(@)C . Calculate the degree of association of acetic acid in benzene. (K_(f)=5.12 K^(@) mol^(-1) kg^(-1))

The freezing point of solution containing 0.2 g of acetic acid in 20.0 g of benzene is lowered by 0.45^(@)C . Calculate the degree of association of acetic acid in benzene. (K_(f)=5.12 K^(@) mol^(-1) kg^(-1))

Read the following paragraph and answer the question given below: Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 KJ/mol. Acetic acid exists partly as dimer in benzene solution. The freezing point of 0.02 mol fraction of acetic acid in benzene is 277.4 K. The molal cryoscopic constant of benzene in K "molality"^(-1) is

Acetic acid associates in benzene to form a dimer. 1.65 g of acetic acid when dissolved in 100 g of benzene raised the boiling point by 0.36^(@)C . Calculate the Van't Hoff factor and degree of association of acetic acid. ( K_(b) for benzene= 2.57^(@)C )

Acetic acid dimerises in benzene solution.The van't Hoff factor for the dimerisation of acetic acid is 0.8. The % of dimerisation of acetic acid is

The freezing point of a solution containing of 0.2g of acetic acid in 20.0g of benzene is lowered 0.45^(@)C . Calculate. (i) the molar mass of acetic acid from this data (ii) Van't Hoff factor [For benzene, K_(f)=5.12K kg "mol"^(-1) ] What conclusion can you draw from the value of Van't Hoff factor obtained ?

On adding 1g arsenic to 80 g benzene, the freezing point of benzene is lowered by 0.213^(@)C . The formula of arsenic molecule is : (Atomic mass of arsenic = 75) ( K_(f) = 5.12 K kg/mol)

2g of benzoic acid dissolved in 25g of benzene shows a depression in freezing point equal to 1.62K. What is the percentage association of benzoic acid if it forms a dimer in solution ? ( K_(f) for benzene = 4.9 K kg "mol"^(-1) )