White vitrol `overset(100^(o)C)rarrXoverset(250^(o)C)rarrY`. If loss in weight in the first step is `A` gm and that of in second step is `B` gm, then `B/A=`

Li+N_(2) overset(Delta)rarrA overset(H_(2)O)rarr B+(C ) gas Then the correctly matched pair for A,B,C are :

Ketones (R-overset(O)overset("||")C-R') can be obtained in one step by (where R and R' are alkyl groups)

C_(5)H_(10)O overset(H_(3)O^(o+))rarrB+C , (B) and (C) both give +ve iodoform test. Compound (A) is :

Consider the statements for given reaction 1. In the first step, there is breaking of C - O bond 2. The second step is S_(N)2 reaction 3. There is retention of configuration in the first step 4. There is inversion of configuration in the second step

In the three steps (a,b,c) of polymerase chain reaction, select the correct step

A+H_(2)Oto NaOH A underset(400^(@)C)overset(O_(2))rarrBunderset(at25^(@)C)overset(H_(2)O)rarrNaOH+O_(2), B is used for oxygenating in submarines A and B are respectively.

A+H_(2)Oto NaOH A underset(400^(@)C)overset(O_(2))rarrBunderset(at25^(@)C)overset(H_(2)O)rarrNaOH+O_(2), B is used for oxygenating in submarines A and B are respectively.

The ubiquitous AM-GM inequality has many applications. It almost crops up in unlikely situations and the solutions using AM-GM are truly elegant . Recall that for n positive reals a_(i) I = 1,2 …, n, the AM-GM inequality tells (overset(n) underset(1)suma_i)/n ge ( overset(n)underset(1)proda_i)^((1)/(n)) The special in which the inequality turns into equality help solves many problems where at first we seem to have not informantion to arrive at the answer . If a,b,c are positive integers satisfying (a)/(b+c)+(b)/(c+a) + (c)/(a+b) = (3)/(2) , then the value of abc + (1)/(abc)

If O is the circumcentre of A B C , then find the value of /_O B C+\ /_B A C

The weight of 250 ml of diatomic gas at 0^∘C and 2 atm pressure is 1 gm. What is the atomic weight of the substance?