Evaluate :

`int ( ( 1 + v^3 ) / - v^3 ) ` dv

Evaluate : int ( (2v ) / ( 1 - v^2 ) ) dv

Evaluate : int (( 2v ) / (v^2 -1) ) dv

Evaluate : 1/3 int ( 1 + 2v ) / ( v^2 + v + 1 )dv

Evaluate : int( 1 / ( 2v^2 - 1 ) ) dv

Evaluate int (dv)/(1+2v)

int e ^ (- (v) / (u)) dv

If u and v are two functions of x then prove that : int uv dx = u int v dx - int [ (du)/(dx) int v dx ] dx Hence, evaluate int x e^(x) dx

int (1-v) (dx)) / (1 + v + v ^ (2))

Evaluate: int_(0)^(1)|5x-3|dx( ii) int_(0)^( pi)|cos x|dx( iii) int_(-5)^(5)|x-2|dx( iv )int_(-1)^(1)e^(|x|)dx(v)int_(0)^(2)|x^(2)+2x-3|dx(v)int_(1)^(4)(|x-1|+|x-2|+|x-3|)dx( vi) int_(1)^(2)|x^(3)-x|dx

Integrate : int((1)/(2v+v^(2)))dv