If `f(x)=(ax+b)/(cx+d), ad-bc!=0` is inverse of itself then

int(ax+b)/(cx+d)dx

Show that f:R-[0]rarr R0[0] given by f(x)=(3)/(x) is invertible and it is inverse of itself.

The value of parameter alpha, for which the function f(x)=1+alpha x,alpha!=0 is the inverse of itself

Let f(x) = (ax +b)/(cx + d) (da-cb ne 0, c ne0) then f(x) has

(d)/(dx)[(ax+b)(cx+d)]=

Let f (x) = (ax+b)/(cx+d), where a,b,c d are non zero If f (7) =7,f (11)=11 and f(f (x))=x for all x except -d/c. The unique number which is not is the range of f is