A uniform sphere of charge Q of radius a has electric potential at distance `(3a)/(2)` from its centre equal to half of its value at distance x from its centre.The value of x is

For a uniformly charged ring of radius R, the electric field on its exis has the largest magnitude at a distance h from its centre. Then value of h is :

The centre of gravity of a hollow cone of height h is at distance x from its vertex where the value of x is:

At what distance 'd' from the surface of a solid sphere of radius 'R', (a)potential is sme as at a distance (R)/(2) from the centre ? (b) field strengt is ame as at a distance (R)/(4) from centre.

The gravitational potential energy of a body at a distance r from the centre of earth is U . Its weight at a distance 2r from the centre of earth is

The magnitude of gravitational potential energy of a body at a distance r from the centre of earth is u. Its weight at a distance 2r from the centre of earth is

A charged disc of radius 3 m has charge density sigma . Electric field at a distance of 4 m from its centre on axis is _______

In the above problem if potential on its surface is .V.. Potential at distance (r )/(2) from its centre is _____

A hollow conducting sphere of radius R has a charge (+Q) on its surface. What is the electric potential within the sphere at a distance r = (R )/(3) from its centre ?

A sphere of radius R carries charge such that its volume charge density is proportional to the square of the distance from the centre. What is the ratio of the magnitude of the electric field at a distance 2 R from the centre to the magnitude of the electric field at a distance of R//2 from the centre?

Assertion: Electric potential on the surface of a charged sphere of radius R is V. Then electric field at distance r=R/2 from centre is V/(2R) . Charge is distributed uniformly over the volume. Reason: From centre to surface, electric field varies linearly with r. Here r is distance from centre.