A uniform magnetic field `-B_(0)hat k` exists to the right of the plane `y=x tan theta` as shown. At t=0 a particle of mass m and positive charge q with velocity `v_(0)` is enters in magnetic field at origin.Then prove that the particle will come out of the magnetic field at t=2θm/qB prove that the Co-ordinate of point from which particle will come out is [(mv/qB)sin2θ,mv/qB(1−cos2θ),0]

A particle of mass m and charge q is projected into a region having a perpendicular magnetic field B. Find the angle of deviation of the particle as it comes out of the magnetic field if ihe width d of the region is (2mv)/(qB)

A particle of mass m and charge q is projected into a region having a perpendicular magnetic, field B . Find the angle of deviation of the particle as it comes out of the magnetic field if the, width of the region is b , which is very slightly less than (mv)/(2Bq)

A particle of mass m and charge q is projected into a region having a perpendicular magnetic field B. Find the angle of deviation fo the particle as it comes out of the magnetic field if the width d of the regions is very smaller then

A particle of mass m and charge q is projected into a region having a perpendicular magnetic field B. Find the angle of deviation fo the particle as it comes out of the magnetic field if the width d of the regions is very smaller then

A non-uniform magnetic field vecB=B_(0)(1+ y/d)(-hatk) is present in the region of space between y=0 and y=d . A particle of mass m and positive charge q has velocity vecv=(3qB_(0)d)/mhati at origin O . Find the angle made by velocity of the particle withe the positive x -axis when it leaves the field. (Ignore any interaction other than magnetic field)

Assertion In a uniform magnetic field B=B_(0)hat(k) , if velocity of a charged particle is v_(0)hat(i) at t = 0, then it can have the velocity v_(0)hat(j) at some other instant. Reason In uniform magnetic field, acceleration of a charged particle is always zero.

A charged particle of mass m and charge q is projected into a uniform magnetic field of induciton vecB with speed v which is perpendicular to vecB . The width of the magnetic field is d. The impulse imparted to the particle by the field is (dlt lt mv//qB)

There exist uniform magnetic field vec(B)=-B_(0)hatk in region of space with 0ltxltd and 2dltxlt3d as shown in the figure. A positive charged particle of mass m and charge q is projected with velocity vec(v)=vhat(i) as shown in the figure. If radius of curvature of path of the charged particle in magnetic field is R(2dltRlt3d) then time elapse by charged particle in magnetic field regions is

A uniform magnetic field barB =B_(0)hatj exists in a space. A particle of mass m and charge q is projected towards negative x-axis with speed v from the a point (d,0,0) The maximum value v for which the particle does not hit y-z plane is .

A uniform mangetic field of strength B exists in a region of width d. A particle of charge q and mass m is shot perpendicularly (as shown in Fig. ) into the magnetic field. Find the time spent by the particle in the magnetic field if (a) dgt (m u)/(qB) (b) dlt (m u)/(qB)