The temperature of a body falls from `40^°`C to `30^°`C in 10 minutes. If temperature of surrounding is `15^°`C, then time to fall the temperature from `30^°`C to `20^°`C

The temperature of a body falls from 40^(@)C to 36^(@)C in 5 minutes when placed in a surrounding of constant temperature 16^(@)C Find the time taken for the temperature of the body to become 32^(@)C .

The excess temperature of a body falls from 12^(@)C to 6^(@)C in 5 minutes, then the time to fall the excess temperature from 6^(@)C to 3^(@)C is (assume the newton's cooling is valid)

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be

A body cools from 60^(@) C to 50^(@) C in 6 minutes, the temperature of the surroundings being 25^(@) C. What will be its temperature after another 6 minutes ?

A liquid cools from 70^(@) C to 60^(@) C in 5 minutes. If the temperautre of the surrounding is 30^(@) C, what is the time taken by the liquid to cool from 50^(@) C to 40^(@) C ?

A body cools from 60^(@)C to 40^(@)C in 7 minutes. Temperature of surrounding is 10^(@)C . After next 7 minutes what will be its temperature ? During whole process Newton's law of cooling is obeyed.

A body takes 10 min to cool douwn from 62^@C to 50^@C . If the temperature of surrounding is 26^@C then in the next 10 minutes temperature of the body will be

If a body cools down from 80^(@) C to 60^(@) C in 10 min when the temperature of the surrounding of the is 30^(@) C . Then, the temperature of the body after next 10 min will be

A system receives heat continuously at the rate of 10 W. The temperature of the system becomes constant at 70^@C when the temperature of the surroundings is 30^@C . After the heater is switched off, the system cools from 50^@C to 49.9^@C in 1 min. The heat capacity of the system is

For one mole of an ideal gas, increasing the temperature from 10^(@)C to 20^(@)C