Solve `(sin^4x+cos^4x+sin^2xcos^2x)-(sin^3x+cos^3x)`

Solve sin 2x=4 cos x .

If y=(sin^4x-cos^4x+sin^2xcos^2x)/(sin^4x+cos^4x+sin^2xcos^2x),x in (0,pi/2) , then (a) -3/2lt=ylt=1/2 (b) 1lt=ylt=1/2 (c) -5/3lt=ylt=1 (d) none of these

Solve (1+sin^2x-cos^2x)/(1+sin^2x+cos^2x)

Solve sin 2x+cos 4x=2 .

Solve sin 2x+cos 4x=2 .

The integral int (sin^2xcos^2x)/(sin^5x+cos^3xsin^2x+sin^3xcos^2x+cos^5x)^2 dx is equal to

Solve sin^(5)x=1+cos^(4)3x

Solve 2 sin^(3) x=cos x .

Evaluate the following integrals: int_0^(pi//4)(sin^2xcos^2x)/((sin^3x+cos^3x)^2)dx

Evaluate: (i) int(sin^3x-cos^3x)/(sin^2xcos^2x)\ dx (ii) int(5cos^3x+6sin^3x)/(2sin^2xcos^2x)\ dx