Solve `[(cosa,sina),(-sina,cosa)]`

Simplify : sinA[(sinA,-cosA),(cosA, sinA)]+cosA[(cosA,sinA),(-sinA, cosA)] .

Prove: (1+cosA)/(sinA)=(sinA)/(1-cosA)

If |(cos(A+B),-sin(A+B),cos2B),(sinA,cosA,sinB),(-cosA,sinA,cosB)|=0 then B =

Prove that : (cosA)/(1+sinA)+(1+sinA)/(cosA)=2secA.

Using properties of determinant. Prove that |[sinA,cosA,sinA+cosB],[sinB,cosA,sinB+cosB],[sinC,cosA,sinC+cosB]|=0

Prove the following identities: (cosA)/(1-sinA)+(sinA)/(1-cosA)+1 = (sinAcosA)/((1-sinA)(1-cosA) ((1+cotA+tanA)(sinA-cosA)/(sec^3A-cos e c^3A)=sin^2Acos^2A

Prove the following identity, where the angles involved are acute angles for which the expressions are defined. (cosA)/(1+sinA)+(1+sinA)/(cosA)=2secA

Prove: (cos e c\ A-sinA)(secA-cosA)(tanA+cotA)=1

Given that 16cotA=12 ; find the value of (sinA+cosA)/(sinA-cosA) .

Solve sinA.cos(A-B)-cosA.sin(A-B)