A plane passes through the points `A(1,2,3),B(2,3,1)`and `C(2,4,2)`. If `O` is the origin and `P` is `(2,-1,1)`, then the projection of `vec OP` on this plane is of length.

Find the equation of plane passes through the point A ( 1,2,1) ,B ( 2,3,1) and C( 2,1,0) Also find the distance of the point (1,1,1)

Find the equation of the plane passing through the points A(2,1,-3), B(-3,-2,1) and C(2,4,-1) .

Find the equation of plane passing through three points A(0, 1, 2), B(3, 4, -1), C(2, 4, 2) in Cartesian form.

Find the equation of the plane through the points A(3, 2, 0), B(1, 3, -1) and C(0, -2, 3).

Find equation of plane passing through the points P(1, 1, 1), Q(3, -1, 2) and R(-3, 5, -4) .

A plane passes through the point (-2, -2, 2) and contains the line joining the points (1, -1, 2) and (1, 1, 1). Then the image of (-7, 2, 3) in the plane is

Statement 1: A plane passes through the point A(2,1,-3)dot If distance of this plane from origin is maximum, then its equation is 2x+y-3z=14. Statement 2: If the plane passing through the point A( vec a) is at maximum distance from origin, then normal to the plane is vector vec adot

Statement 1: A plane passes through the point A(2,1,-3)dot If distance of this plane from origin is maximum, then its equation is 2x+y-3z=14. Statement 2: If the plane passing through the point A( vec a) is at maximum distance from origin, then normal to the plane is vector vec adot

Statement 1: A plane passes through the point A(2,1,-3)dot If distance of this plane from origin is maximum, then its equation is 2x+y-3z=14. Statement 2: If the plane passing through the point A( vec a) is at maximum distance from origin, then normal to the plane is vector vec adot

Let P be a plane passing through the points (2,1,0) (4,1,1) and (5,0,1) and R be any point (2,1,6) . Then the image of R in the plane P is :