A ray of monochromatic light is incident on an equilateral glass prism `(mu=sqrt(2))` in the position of minimum deviation.The angle (in degree) of minimum deviation is

A ray of light is incident on an equilateral glass prism placed on a horizontal table. For minimum deviation which of the following is true:

A beam of monochromatic light is incident at i= 50^(@) on one face of an equilateral prism, the angle of emergence is 40^(@) , then the angle of minimum deviation is :

A monochromatic light is incident at a certain angle on an equilateral triamgular prism and suffers minimum deviation . If the refractive index of the material of the prism is sqrt(3) , them the angle of incidence is :

A ray of light incident on an equilateral triangular glass prism of mu = sqrt(3) moves parallel to the base of the prism inside it. What is the angle of incidence for this ray ?

A light ray of yellow colour is incident on an equilateral glass prism at an angle of incidence equal to 48^(@) and suffers minimum deviation by an angle of 36^(@) . (i) What will be the angle of emergence ? (ii) If the angle of incidence is changed to (a) 30^(@) (b) 60^(@) , state in each case whether the angle of deviatioin will be equal to, less than or more than 36^(@) . ?

A light ray is normally incident onone face of equilateral glass prism of refractive index sqrt(2) . The deviation of light ray is

An equilateral prism produces a minimum deviation of 30^(@) . The angle of incidence is

The refractive index of the material of prism sqrt3, then the angle of minimum deviation of prism is

A ray of light incident at an angle of incidence 48^(@) on a prism of refracting angle 60^(@) suffers minimum deviation. Calculate the angle of minimum deviation.

A ray of light passing through an equilateral triangular glass prism from air undergoes minimum deviation when angle of incidence is 3//4 th of the angle of prism. Calculate the speed of light in the prism.