A particle moves in the X - Y plane under the influence of a force `vec F`such that its instantaneous momentum is `vec p=hat i2 cost +hat j2sin t` .What is the angle between the force and instantaneous momentum?

A particle moves in the xy plane under the influence of a force such that its linear momentum is vecP(t) = A [haticos(kt)-hatjsin(kt)] , where A and k are constants. The angle between the force and momentum is

A particle moves in the x-y plane under the action of a force vec F such that its linear momentum vec P at any time t is vec P=2cost hati+2sint hatj . The angle between vec F and vec P at a given time t will be

A particle moves in the x-y plane under the action of a force vecF such that the value of its linear momentum vecP at any time t is P_(x)=2 cost and p_(y)=2sint . What is the angle theta between vecF and P at a given time t?

A particle moves in the x-y plane under the action of a force vecF such that the value of its linear momentum vecP at any time t is P_(x)=2 cost and p_(y)=2sint . What is the angle theta between vecF and P at a given time t?

A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t and p_(x)=2cos t, p_(y)=2sin t. the angle between F and p at time t is

If |a|=2,|b|=7 and vec a x vec b=3 hat i+2 hat j+6 hat k , find the angle between vec a and vec b .

A particle move in x-y plane such that its position vector varies with time as vec r=(2 sin 3t)hat j+2 (1-cos 3 t) hat j . Find the equation of the trajectory of the particle.

A particle of mass 2 kg moves in the xy plane under the action of a constant force vec(F) where vec(F)=hat(i)-hat(j) . Initially the velocity of the particle is 2hat(j) . The velocity of the particle at time t is

If vec(a) = hat(i) - 2 hat(j) + 3 hat(k) and vec(b) = 2 hat(i) - 3 hat(j) + 5 hat(k) , then angle between vec(a) and vec(b) is

If vec r=x hat i+y hat j+z hat k ,\ then write the value of | vec rxx hat i|^2dot