The value of escape velocity of a certain planet is `sqrt(2)``(km)`/`s`.Then the value of orbital speed for a satellite orbiting closer to its surface is ?

The value of escape speed from certain planet is 4 km/s. What will be the orbital speed of a satellite orbiting close to its surface ?

The value of escape speed from certain planet is 4 km/s. What will be the orbital speed of a satellite orbiting close to its surface ?

The value of escape speed from the surface of earth is

Define orbital velocity. Obtain the relation between orbital velocity and acceleration due to gravity g, for a satellite orbiting very close to the surface of the earth.

A bullet is fired vertically upwards with a velocity upsilon from the surface of a spherical planet when it reaches its maximum height, its acceleration due to the planet's gravity is (1)/(4)th of its value at the surface of the planet. If the escape velocity from the planet is V_("escape") = upsilon sqrt(N) , then the value of N is : (ignore energy loss due to atmosphere).

The orbital velocity of an artificial in a circular orbit just above the earth's surface v. For a satellite orbiting at an altitude of half the earth's radius the orbital velocity is

An artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of escape velocity from the surface of earth. R is the radius of earth and g is acceleration due to gravity at the surface of earth. (R=6400 km). The time period of revolution of satellite in the given orbit is

Mass and radius of a planet are two times the value of earth. What is the value of escape velocity from the surface of this planet?

A geo-stationary satellite orbits around the earth in a circular orbit of radius 36000 km. Then, the time period of a spy satellite orbiting a few hundred kilometers above the earth's surface (R_("Earth") = 6400 " km") will approximately be

How many times is escape velocity (V_(e)) , of orbital velocity (V_(0)) for a satellite revolving near earth