Find the equation of the normal to the curve `x^(2/3)+y^(2/3)=2` at the point `(1,1)`

Find the equation of the normal to the curve y=x^(3)-3x at (2,3).

The equation of the normal to the curve 2y+x^(2)=3 at the point (1,1) is

Find the equation of the normal to the curve ay^(2)=x^(3), at the point (am^(2),am^(3)). If normal passes through the point (a,0) then find the slope.

Find the equation of the normal to the curve ay^(2)=x^(3) at the point (am^(2), am^(3)) .

Find the equation of the normal to the curve y=2x^(2)+3sin x at x=0.

The equation of normal to the curve, x^(2//3)+y^(2//3)=a^(2//3) at the point (a,0) is

If 3x+4y-k is the equation of the normal to the curve x^(2)+2x-3y+3=0 at the point (1,2) ,then the value of k=

Find the equation of tangent and normal to the curve y =3x^(2) -x +1 at the point (1,3) on it.

Find the equation of tangent and normal to the curve x^((2)/(3))+y^((2)/(3))=2 at (1,1)

Find the equation of the normal to the curve a y^2=x^3 at the point (a m^2,\ a m^3) .