If the time period t of the oscillation of a drop of liquid of density d, radius r, vibrating under surface tension s is given by the formula `t=sqrt(r^(2b)s^(c)d^(a//2))`. It is observed that the time period is directly proportional to `sqrt((d)/(s))` . The value of b should therefore be :

Time period of an oscillating drop of radius r, density rho and surface tension T is t=ksqrt((rhor^5)/T) . Check the correctness of the relation

The time period of a soap bubble is T which depneds on pressure p density d and surface tension s then the relation for T is

The time period of oscillation T of a small drop of liquid under surface tension depends upon the density rho , the radius r and surface tension sigma . Using dimensional analysis show that T prop sqrt((rhor^(3))/(sigma))

A liquid drop of density rho , radius r , and surface tension sigma oscillates with time period T . Which of the following expressions for T^(2) is correct?

If the time period (T) of vibration of a liquid drop depends on surface tension (S) , radius ( r ) of the drop , and density ( rho ) of the liquid , then find the expression of T .

If T_(1) and T_(2) are the time-periods of oscillation of a simple pendulum on the surface of earth (of radius R) and at a depth d, the d is equal to

The time period (T) of small oscillations of the surface of a liquid drop depends on its surface tension (s), the density (rho) of the liquid and it's mean radius (r) as T = cs^(x) p^(y)r^(z) . If in the measurement of the mean radius of the drop, the error is 2 % , the error in the measurement of surface tension and density both are of 1% . Find the percentage error in measurement of the time period.

The time period of oscillation of a simple pendulum is sqrt(2)s . If its length is decreased to half of initial length, then its new period is

In terms of time period of oscillations T, find the shortest time in moving a particle from + (A)/(2) to -(sqrt(3))/(2) .

A planet is revolving around the sun in a circular orbit with a radius r. The time period is T .If the force between the planet and star is proportional to r^(-3//2) then the quare of time period is proportional to