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If a dipole enclosed by a surface then i...

If a dipole enclosed by a surface then its flux is

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Assertion : If a dipole is enclosed by a surface, then according to Gauss's law, electric flux linked with it will be zero. Reason : The charge enclosed by a surface is zero.

When a 10 muC charge is enclosed by a closed surface, the flux passing through the surface is phi . Now another 10 µC charge is placed inside the closed surface, then the flux passing through the surface is ______.

If a charge is enclosed by the surface of the sphere then total flux emitted from the surface will be:

An electric dipole of diople moment 20xx10^(-6)C m is enclosed by a closed surface. What is the net electric flux coming out of the surface ?

Assertion : Total flux through a closed surface is zero if no charge is enclosed by the surface. Reason : Gauss law is true for any closed surface, no matter what its shape or size is.

A closed surface encloses a net charge of -3.60 muC . What is the net electric flux through the surface? (b) The electric flux through a closed surface is found to be 780 N-m^2//C . What quantity of charge is enclosed by the surface? (c) The closed surface in part (b) is a cube with sides of length 2.50 cm. From the information given in part (b), is it possible to tell where within the cube the charge is located? Explain.

Figure shows three point charges +2q,-q and +3q. Two charges +2q and -q are enclosed within a surface .S.. What is the electric flux due to this configuration through the surface.S?

This question contains Statement -1 and Stantement -2 Of the four choices given after the statements, choose the one that best desctibes the two statemesnts. Statement -1: For a mass M kept at the center of a cube of side 'a', the flux of gravitational field passing through its sides 4piGM. Statement -2: If the direction of a field due to a point source is radial and its dependence on the distance 'r' from the source is given as (1)/(r^2) , its flux through a closed surface depends only on the strength of the source enclosed by the surface and not on the size or shape of the surface.

A charge Q is enclosed by a Gaussian surface. If surface area is doubled and charge Q is tripled then the outward electric flux will

If the electric flux entering and leaving an enclosed surface respectively is phi_1 and phi_2 , the electric charge inside the surface will be