Non - Finite Verb | Gerund - Infinite - Participle Part 1.. Basic English Grammar | All Competitive Exams
Non - Finite Verb | Gerund - Infinite - Participle Part 1.. Basic English Grammar | All Competitive Exams
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Sentence : Type & Parts || Day 1 || Class 10 English Grammar || UP Board Exam 2022
State whether the given set is finite or infinite. Set of all points on a line segment 1 cm long .
Write the finite and infinite sets from the following sets : (i) Set of all natural numbers (ii) Set of all positive integers less than 100 (iii) {x : x = x^(2)} (iv) Set of all lines parallel to x-axis (v) Set of all prime numbers less then 100 (vi) {x : x^(2)=16} (vii) {x : x in R,1 le x le 10} (viii) Set of all negative integers less than 50.
The members of a chess club took part in a round robin competition in which each player plays with other once. All members scored the same number of points, except four juniors whose total score ere 17.5. How many members were there in the club? Assume that for each win a player scores 1 point, 1/2 for a draw, and zero for losing.
The members of a chess club took part in a round robin competition in which each player plays with other once. All members scored the same number of points, except four juniors whose total score ere 17.5. How many members were there in the club? Assume that for each win a player scores 1 point, 1/2 for a draw, and zero for losing.
"Equivalent mass" =("Molecular mass/Atomic mass" )/("n-factor") n-factor is very important in redox as well as non-redox reactions.With the help of n-factor we can predict the molar ratio of the reactant species specis taking part in reactions. The reciprocal of n-factor's ratio of the reactions is the molar ratio of the reactants. In general n-factor of acid/base is number of moles of H^(+)//OH^(-) furnished per mole of acid/base n-factor of a reactant is number of moles electrons lost or gained per mole of reactant. Example 1: (1)In acidic medium : KMnO_(4) (n=5)to Mn^(2+) (2) In neutral medium : KMnO_(4)(n=3) to Mn^(2+) (3) In basic medium : KMnO_(4)(n=1) to Mn^(6+) Example 2 : FeC_(2)O_(4)to Fe^(3+)+2CO_(2) Total number of moles e^(-) lost by 1 mole of FeC_(2)O_(4) =1+1xx2 implies 3 For the reaction, O("molar mass=M") to Fe_(2)O_(3) what is the eq. mass of fe_(0.95) O ?
"Equivalent mass" =("Molecular mass/Atomic mass" )/("n-factor") n-factor is very important in redox as well as non-redox reactions.With the help of n-factor we can predict the molar ratio of the reactant species specis taking part in reactions. The reciprocal of n-factor's ratio of the reactions is the molar ratio of the reactants. In general n-factor of acid/base is number of moles of H^(+)//OH^(-) furnished per mole of acid/base n-factor of a reactant is number of moles electrons lost or gained per mole of reactant. Example 1: (1)In acidic medium : KMnO_(4) (n=5)to Mn^(2+) (2) In neutral medium : KMnO_(4)(n=3) to Mn^(2+) (3) In basic medium : KMnO_(4)(n=1) to Mn^(6+) Example 2 : FeC_(2)O_(4)to Fe^(3+)+2CO_(2) Total number of moles e^(-) lost by 1 mole of FeC_(2)O_(4) =1+1xx2 implies 3 In the reaction, xVO+yFe_(2)O_(3) to FeO+V_(2)O_(5) what is the value of x and y respectively?
"Equivalent mass" =("Molecular mass/Atomic mass" )/("n-factor") n-factor is very important in redox as well as non-redox reactions.With the help of n-factor we can predict the molar ratio of the reactant species specis taking part in reactions. The reciprocal of n-factor's ratio of the reactions is the molar ratio of the reactants. In general n-factor of acid/base is number of moles of H^(+)//OH^(-) furnished per mole of acid/base n-factor of a reactant is number of moles electrons lost or gained per mole of reactant. Example 1: (1)In acidic medium : KMnO_(4) (n=5)to Mn^(2+) (2) In neutral medium : KMnO_(4)(n=3) to Mn^(2+) (3) In basic medium : KMnO_(4)(n=1) to Mn^(6+) Example 2 : FeC_(2)O_(4)to Fe^(3+)+2CO_(2) Total number of moles e^(-) lost by 1 mole of FeC_(2)O_(4) =1+1xx2 implies 3 Consider the following reaction. H_(3)PO_(2)+NaOH to NaH_(2)PO_(2)+H_(2)O What is the equivalent mass of H_(3)PO_(2) ?(mol.Wt.is M)
"Equivalent mass" =("Molecular mass/Atomic mass" )/("n-factor") n-factor is very important in redox as well as non-redox reactions. With the help of n-factor we can predict the molar ratio of the reactant species taking part in reactions. The reciprocal of n-factor's ratio of the reactions is the molar ratio of the reactants. In general n-factor of acid/base is number of moles of H^(+)//OH^(-) furnished per mole of acid/base n-factor of a reactant is number of moles electrons lost or gained per mole of reactant. Example 1: (1)In acidic medium : KMnO_(4) (n=5)to Mn^(2+) (2) In neutral medium : KMnO_(4)(n=3) to Mn^(2+) (3) In basic medium : KMnO_(4)(n=1) to Mn^(6+) Example 2 : FeC_(2)O_(4)to Fe^(3+)+2CO_(2) Total number of moles e^(-) lost by 1 mole of FeC_(2)O_(4) =1+1xx2 implies 3 n-factor of Ba(MNO_(4))_(2) in acidic medium is :
Given C_(1) lt C_(2) lt C_(3) lt C_(4) lt C_(5) and the function y=f(x) is twice differentiable . f'(x) gt 0 " for " x in (C_(2),C_(4)), f'(C_(2))=f'(C_(4))=0 and f'(x) lt 0 for all the remaining values. Also f''(C_(1))=f''(C_(3))=f''(C_(5))=0 and f''(x) gt 0 for x in (C_(1),C_(3)) cup (C_(5), oo) and f''(x) lt 0 for remaining values. Answer the following: (i) What is the minimum number of asymptotes parallel to the x-axis for y=f(x) ? (ii) What is the maximum number of asymptotes parallel to the x-axis of y=f(x) ? (iii) If the range of y=f(x) is [a, b], a , b in R , then what is the minimum number of asymptotes parallel to the x-axis of y=f(x) ? (iv) If the range of y=f(x) is non-finite interval, then what is the maximum number of asymptotes parallel to the x-axis ?
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