The motion of a particle executing simple harmonic motion is described by the displacement function, . If the initial position of the particle is 1 cm and its initial velocity is , what are its amplitude and initial phase angle?
The angular frequency of the particle is . If instead of the cosine function, we choose the sine function to describe the SHM: , what are the amplitude and initial phase of the particle with the above initial conditions?

The motion of a particle in S.H.M. is described by the displacement function, x=Acos(omegat+phi) , If the initial (t=0) position of the particle is 1cm and its initial velocity is omega cm s^(-1) , what are its amplitude and initial phase angle ? The angular frequency of the particle is pis^(-1) . If instead of the cosine function, we choose the sine function to describe the SHM : x=B sin(omegat+alpha) , what are the amplitude and initial phase of the particle with the above initial conditions ?

While a particle executes linear simple harmonic motion

For a particle executing simple harmonic motion, the acceleration is -

In simple harmonic motion,the particle is

A particle executing SHM is described by the displacement function x(t)=Acos(omegat+phi) , if the initial (t=0) position of the particle is 1 cm, its initial velocity is pi" cm "s^(-1) and its angular frequency is pis^(-1) , then the amplitude of its motion is

The differential equation of a particle executing simple harmonic motion along y-axis is

For a particle executing simple harmonic motion, the acceleration is proportional to

For a particle executing simple harmonic motion, which of the following statements is not correct

A particle is executing simple harmonic motion. Its total energy is proportional to its

A particle is executing simple harmonic motion with an amplitude A and time period T. The displacement of the particles after 2T period from its initial position is