If an air bubbles rises from the bottom of a mercury tank to the top its volume become `1(1)/(2)` times.When normal pressure is "76cm" of "Hg" then the depth of the "Hg" tank is

As an air bubble rises from the bottom of a lake to the surface, its volume is doubled. Find the depth of the lake. Take atmospheric pressure = 76 cm of Hg.

An air bubble rises the bottom of a lake to the top and increases thereby its volume 15 times . If the atmospheric pressure is 75 cm of hg and density of lake water is 1.02 xx10^(3) kg//m^(3) then find the depth of lake ( Neglect surface tension).

When a large bubble rises from the bottom of a lake to the surface, its radius doubles, The atmospheric pressure is equal to that of a column of water of height H. The depth of the lake is

When an air bubble rise from the bottom of a deep lake to a point just below the water surface, the pressure of air inside the bubble

The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1//10 of the density of mercury, the depth of the lake is

A air bubble rises from bottom of a lake to surface. If its radius increases by 200% and atmospheric pressure is equal to water coloumn of height H, then depth of lake is

When an air bubble of radius 'r' rises from the bottom to the surface of a lake, its radius becomes 5r//4 (the pressure of the atmosphere is equal to the 10 m height of water column). If the temperature is constant and the surface tension is neglected, the depth of the lake is

An air bubble in a water tank rises from the bottom to the top. Which of the following statements are true?

An air bubble has a radius of 0.50 cm at the bottom of a water tank where the temperature is 280 K and the pressure is 280 kPa. When the bubble rises to the surface, the temperature changes to 300 K and pressure to 300 K and pressure to 100 kPa. Calculate the radius of the bubble at the surface