When 3g of Mg reacts with excess of dil.HCl,the weight of `H_(2)` liberated is ( at.Wt.of Mg=24)

5 g of Zn reacts with (I) Excess of NaOH (II) Dilute HCl, then volume ratio of H_2 gas evolved in (I) and (II) is

0.9 g Al reacts with dil. HCl to give H_(2) . The volume of H_(2) evolved at STP is (Atomic weight of Al = 27)

1 g of an alloy of Al and Mg reacts with excess HCl to form AlCl_(3) , MgCl_(2) , and H_(2) . The evolved H_(2) collected over mercury at 0^(@)C occupied 1200 mL at 699 mm Hg . What is the composition of alloy?

1.0 g of an alloy of Al and Mg when treated with excess of dil HCl gave MgCl_(2), AlCl_(3) and hydrogen. Evolved hydrogen collected over Hg at 0^(@)C has a volume of 1.20 litres at 0.92 atm pressure. The percentage of Aluminium in the alloy is :

The magnitude of work done (in kcal) when 120 gm of Mg (s) is reacted with excess of hydrochloric acid in an open vessel at 27^@C is

When aniline reacts with NaNO_2 and dil. HCl at 0^@-%^2C , the product formed is

A 1.458 g of Mg reacts with 80.0 ml of a HCl solution whose pH is -0.477.The change in pH when all Mg has reacted.(Assume constant volume. Mg=24.3g//"mol". )(log 3=0.47, log2= 0.301)

Mg liberates H_(2) on reaction with

Mg liberates H_(2) on reaction with

When BrO_(3)^(-) ion reacts with Br^(-) iron in acid solution Br_(2) is liberated. The equivalent weight of KBrO_(3) in this reaction is: