A platinum resistance thermometer reads `0^(@)` when its resistance is `80Omega` and `100^(@)` when its resistance is `90Omega`.The temperature at the platinum scale at which the resistance is `86Omega` is `N times10^(@)` .Then the value of `N` is

A platinum resistance thermometer reads 0^@ when its resistance is 80 Omega and 100^@ when its resistance is 90 Omega . Find the temperature at the platinum scale at which the resistance is 86 Omega .

A platinum resistance thermometer reads 0^@ C when its resistance is 80 Omega and 100^@ C when its resistance is 90 Omega . Find the temperature at which the resistance is 86 Omega .

The electrical resistance of pure platinum increases linearly with increasing temperature over a small range of temperature . This property is used in a Platinum resistance thermometer. The relation between R_(theta) (Resistance at theta K) and R_(0) (Resistance at theta_(0)K ) is given by R_(theta)=R_(0)[1+a(theta-theta_(0))] , where alpha= temperature coefficient of resistance. Now, if a Platinum resistance thermometer reads 0^(@)C when its resistance is 80Omega and 100^(@)C when its resistance is 90 Omega find the temperature at which its resistance is 86Omega .

The resistance of a platinum wire of platinum resistance thermometer at the ice point is 5 Omega and at steam point is 5.23 Omega . When therometer is insertes in a hot bath, the resistance of the platinum wire is 5.795 Omega . Calculate the temperature of the bath?

A copper coil has resistance of 20.0 Omega at 0^@C and a resistance of 26.4 Omega at 80^@C . Find the temperature coefficient of resistance of copper.

A wire has a resistance of 2.5Omega at 28^(@)C and a resistance of 2.9Omega at 100^(@)C . The temperature coefficient of resistivity of material of the wire is

The temperature coefficient of resistance of a wire is 0.00145^(@)C^(-1) . At 100^(@)C its resistance is 2Omega . At what temperature the resistance of the wire be 3Omega ?

The resistance of a wire at 20^(@)C is 20Omega and at 500^(@)C is 60Omega . At which temperature its resistance will be 25Omega ?

A coil of wire has a resistance of 25.00Omega at 20^@ C and a resistance of 25.17Omega at 150^@C . What is its temperauture cofficient of resistance?

A given wire of resistance 1 Omega is stretched to double its length. What will be its new resistance ?