The radius of the planet is three times the radius of the earth and it has the same average density as that of the earth . the ratio of escape speed from surface of the planet and that from the surface of earth is

The value of escape speed from the surface of earth is

The radius of orbit of a planet is two times that of the earth. The time period of planet is

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. If the escape velocity from the earth is v , then the escape velocity from the planet is:

If the density of the planet is double that of the earth and the radius 1.5 times that of the earth, the acceleration due to gravity on the planet is

Two escape speed from the surface of earth is V_(e) . The escape speed from the surface of a planet whose mass and radius are double that of earth will be.

Gravitational acceleration on the surface of a planet is (sqrt6)/(11)g. where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is (2)/(3) times that of the earth. If the escape speed on the surface of the earht is taken to be 11 kms^(-1) the escape speed on the surface of the planet in kms^(-1) will be

Suppose that the acceleration of a free fall at the surface of a distant planet was found to be equal to that at the surface of the earth. If the diameter of the planet were twice the diameter of the earth, then the ratio of mean density of the planet to that of the earth would be

The mass of a planet is twice the mass of earth and diameter of the planet is thrie the diameter of the earth, then the acceleration due to gravity on the planet's surface is

The escape velocity of a body from the surface of the earth is equal to