find the value of n , `(2/3)^3 times (2/3)^5 =(2/3)^(n-2)`

3.Find the value of (5^0 +4^-1) times 2^2

Find the value of the (-2)^(3)xx5^(2)

Find the value of n : (2^(3)xx5^(n+1)xx10^(2)xx5^(n-1))/(125xx5^(n-2)xx2^(7))=(25)/(4)

Find the value of the 2^(3)xx (-3)^(2) .

Find the value of n, given : (2xx4^(3)xx2^(n-4)xx3xx2^(n+2))/(3^(3)xx2^(16))=(2)/(9)

find the value of n, given : (4^(n-2)xx2^(n-5)xx6xx2^(n+3))/(3xx6^(2))=(4)/(18)

(i) If (n!)/(2.(n-2)!): (n!)/(4!.(n-4)!) = 2:1 , find the valye of n. (ii) If ((2n)!)/(3!(2n-3)!): (n!)/(2!(n-2)!) = 44:3 , then find the value of n.

Simplify: find the value of n (n)/(2)-(3n)/(4)+(5n)/(6)=21

find the value of ( 3 + sqrt3 ) xx ( 2 + sqrt2 )

Find n such that (2/3)^3xx(2/3)^5=(2/3)^n^(-2) ((125)/8)^5xx((125)/8)^n=(5/2)^(18)