If `P(X) = 0.5 ` and `X=4` then ` E(x)` =?

If p(x)=4x-6 and p(a)=0 , then a=

The random variable X can take only the values 0, 1,2 . Given that P(X=0) = P(X=1) = p and that E(X^2) = E(X) ; find the value of p .

If X is a binomial variate with n = 7 and P(X=3)=P(X=4) then P(X=5)=

The random variable X can take only the values 0, 1, 2. Given that P(X=0) = P(X= 1) = p and E(X^2) = E(X) , then find the value of p

For a binomial variate X , if n = 4 and P(X=0) = 16/81 then P(X =4) is

The random variable X can take only the values 0,1,2. If P(X=0)=P(X=1)=p and E(X^(2))=E[X] , then find valu of p.

Let a,b,c, d be the roots of x ^(4) -x ^(3)-x ^(2) -1=0. Also consider P (x) =x ^(6)-x ^(5) -x ^(3) -x ^(2) -x, then the value of p (a) +p(b) +p(c ) +p(d) is equal to :

If e^(sin x)-e^(-sin x)-4=0 , then x= (a) 0 (b) sin^(-1){(log)_e(2+sqrt(5))} (c) 1 (d) none of these

P(x) is a non-zero polynomial such that P(0)=0 and P(x^3)=x^4P(x),P'(1)=7 and int_0^1P(x)=1.5 then int_0^1P(x) P'(x) dx =

If 3f(x)-f((1)/(x))= log_(e) x^(4) for x gt 0 ,then f(e^(x))=