A car weighing 500kg climbs up a hill of slope 1 in 49 with a velocity of 36KMPH .If the frictional force is 50N,the power delivered by the engine is (inkW)

A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km/hr . The centripetal force is

A lorry of mass 2000 kg is traveling up a hill of certain height at a constant speed of 10 m/s. The frictional resistance is 200 N, then the power expended by the coolie is : (g=10 m//s^(2))

A car weighing 1000 kg is going up an incline with a slope of 2 in 25 at a steady speed of 18 kmph . If g = 10 ms^(-2) , the power of its engine is

A car of mass 500kg moving with a speed 36kmh in a straight road unidirectionally doubles its speed in 1min . Find the power delivered by the engine.

A 500-kg car, moving with a velocity of 36kmh^-1 on a straight road unidirectionally, doubles its velocity in 1min . The average power delivered by the engine for doubling the velocity is

A train of mass 400 tons climbs up an incline of 1//49 at the rate of 36kmh^(-1) . The force of friction is 4kg' at per ton. Find the power of the engine.

Amit weighing 60 kgf climbs up a ladder of height 10 m in 15 minutes. Calculate the increase in his potential energy and the power spent by him. Take 1 kgf = 10 N.

A 30 kg block is to be moved up an inclined plane at an anglue 30° to the horizontal with a velocity of 5ms^(-1) . If the frictional force retarding the motion is 150N find the horizontal force required to move the block up the plane. ( g=10ms^(-2) )

An engine of one metric ton is going up an inclined plane, 1 in 2 at the rate of 36 kmph. If the coefficient of friction is 1//sqrt(3) , the power of engine is

A 10 metric ton truck drives up a hilly road of gradient 1 in 50 at a speed of 36kmh^(-1) if the coefficient of kinetic friction between the road and tyres is 0.2, calculate the power delivered by the engine (g=10ms^(-2))