A raindrop of radius 0.2cm is falling through air with a terminal velocity of 8.7m/s.The viscosity of air in SI units is, [`rho_(water)`=`1000(kg)/m^(3)` and,`rho_(air)`=`1(kg)/m^(3)`

A rain drop of radius 0.3 mm falls through air with a terminal viscosity of 1 m s^(-1) . The viscosity of air is 18 xx 10^(-5) poise. The viscous force on the rain drop is

A rain drop of radius 0.3 mm has a terminal velocity in air 1m/s. the viscosity of air is 18xx10^(-5) poise. The viscous force on it is-

A viscous force of 1.018 xx 10^(-7) N acting on a raindrop makes it fall through air with a terminal velocity of 1 ms^(-1) . If the viscosity of air is 0.018 xx 10^(-3) PI, what is the radius of the raindrop? Hint : Stokes' law

A solid sphere falls with a terminal velocity of 10 m//s in air. If it is allowed to fall in vacuum.

An oil drop falls through air with a terminal velocity of (5xx10^(-4))/(sec) viscosity of air is 1.8xx10^(-5)(N-s)/(m^(2)) and density of oil is 900 kg m^(3) neglect density of air as compared to that of oil.

An oil drop falls through air with a terminal velocity of (5xx10^(-4))/(sec) viscosity of air is 18xx10^(-5)(N-s)/(m^(2)) and density of oil is 900 kg m^(3) neglect density of air as compared to that of oil.

A raindrop of radius 0.2 mm falls through air: If the viscosity of air is 18 xx 10^(-6) Pl, find the viscous drag acting on the drop when its speed is 1 m s^(-1) .

Two drops of the same radius are falling through air with a steady velcoity of 5 cm s^(-1). If the two drops coalesce, the terminal velocity would be

Eight drops of water, each of radius 2mm are falling through air at a terminal velcity of 8cms^-1 . If they coalesce to form a single drop, then the terminal velocity of combined drop will be

n drops of water, each of radius 2 mm , fall through air at a terminal velocity of 8 cms^(-1) If they coalesce to form a single drop, then the terminal velocity of the combined drop is 32 cms^(-1) The value of n is