A stone is thrown from point O on ground with velocity `vec v=5hat i+10hat j` m/s where x is horizontal and y vertical.Its angular velocity about O when the stone is at maximum height of its trajectory,is

A particle of mass m is projected with velocity v at an angle theta with the horizontal. Find its angular momentum about the point of projection when it is at the highest point of its trajectory.

A body of mass m is projected with a velocity u at an angle theta with the horizontal. The angular momentum of the body, about the point of projection, when it at highest point on its trajectory is

A particle is moving with velocity vecv = k( y hat(i) + x hat(j)) , where k is a constant . The genergal equation for its path is

A particle is moving with velocity vecv = k( y hat(i) + x hat(j)) , where k is a constant . The genergal equation for its path is

A particle is moving with velocity vecv = k( y hat(i) + x hat(j)) , where k is a constant . The genergal equation for its path is

A stone is thrown upwards with velocity 25m/s. Another stone is simultaneously thrown downward from the same point with speed 10 m/s. When the first stone is at a height 10 m. what is the relative velocity of first stone w.r.t second ?

Two stones are thrown from the same point with velocity of 5 ms^(-1) one vertically upwards and the other vertically downwards. When the first stone is at the highest point the relative velocity of the second stone with respect to the first stone is,

A stone is projected from level ground at t=0 sec such that its horizontal and vertical components of initial velocity are 10(m)/(s) and 20(m)/(s) respectively. Then the instant of time at which tangential and normal components of acceleration of stone are same is: (neglect air resistance) g=10(m)/(s^2) .

A stone is projected from level ground at t=0 sec such that its horizontal and vertical components of initial velocity are 10(m)/(s) and 20(m)/(s) respectively. Then the instant of time at which tangential and normal components of acceleration of stone are same is: (neglect air resistance) g=10(m)/(s^2) .

Find the potential V of an electrostatic field vec E = a(y hat i + x hat j) , where a is a constant.