The potential energy (in joule) of a body of mass 2kg moving in the x -y plane is given by U=6x+8y. Where the position coordinates x and y are measured in metre.If the body is at rest at point (6m,4m) at time t=0,it will cross the y-axis at time t equal to

The potential energy of a particle of mass 2 kg moving in a plane is given by U = (-6x -8y)J . The position coordinates x and y are measured in meter. If the particle is initially at rest at position (6, 4)m, then

The potential energy U in joule of a particle of mass 1 kg moving in x-y plane obeys the law U = 3x + 4y , where (x,y) are the co-ordinates of the particle in metre. If the particle is at rest at (6,4) at time t = 0 then :

The potential energy varphi , in joule, of a particle of mass 1kg , moving in the x-y plane, obeys the law varphi=3x+4y , where (x,y) are the coordinates of the particle in metre. If the particle is at rest at (6,4) at time t=0 , then

The potential energy of body of mass 2 kg moving along the x-axis is given by U = 4x^2 , where x is in metre. Then the time period of body (in second) is

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

The potential energy of a particle of mass 1 kg moving in X-Y plane is given by U=(12x+5y) joules, where x an y are in meters. If the particle is initially at rest at origin, then select incorrect alternative :-

The potential energy phi in joule of a particle of mass 1 kg moving in x-y plane obeys the law, phi=3x + 4y . Here, x and y are in metres. If the particle is at rest at (6m, 8m) at time 0, then the work done by conservative force on the particle from the initial position to the instant when it crosses the x-axis is . a) 25 J b) 25 J c) 50 J d) - 50 J

The potential energy of an object of mass m moving in xy plane in a conservative field is given by U = ax + by , where x and y are position coordinates of the object. Find magnitude of its acceleration :-

Velocity of a body of mass 2kg moving in x-y plane is given by vecv=(2hati+4thatj)m//s , where t is the time in second. The power delivered to the body by the resultant force acting on it at t=5sec is.