Conversion of one molecule of glucose into two molecules of pyruvic acid takes place in :

Options

A. Cytoplasm
B. Mitochondria
C. Endoplasmic reticulum
D. Golgi bodies

Explanation

To solve the question regarding the conversion of one molecule of glucose into two molecules of pyruvic acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Process**: The conversion of glucose to pyruvic acid is a metabolic process. The specific process that converts glucose into pyruvate is known as glycolysis.

2. **Location of Glycolysis**: Glycolysis occurs in the cytoplasm of the cell. This is important because it is the site where glucose is broken down in both aerobic (with oxygen) and anaerobic (without oxygen) conditions.

3. **Understanding the Role of Other Organelles**:
- **Mitochondria**: While mitochondria are involved in further breakdown of pyruvate (in the Krebs cycle), they are not the site where glycolysis occurs.
- **Endoplasmic Reticulum**: This organelle is primarily involved in protein synthesis and lipid metabolism, not in glycolysis.
- **Golgi Apparatus**: Its main function is packaging and transporting proteins, not involved in the glycolysis process.

4. **Conclusion**: Since glycolysis takes place in the cytoplasm, the answer to the question is that the conversion of one molecule of glucose into two molecules of pyruvic acid occurs in the cytoplasm.

### Final Answer:
The conversion of one molecule of glucose into two molecules of pyruvic acid takes place in the **cytoplasm**.

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