Std 6 social science ch.8 bharat varshani bhavyata swadhyay solution, dhoran 6 samajik vigyan chapter 8,ધોરણ 6 સામાજિક વિજ્ઞાન પાઠ 8 ભારતવર્ષની ભવ્યતા સ્વાધ્યાય સોલ્યુશન,gujarat board

Calculate the ratio of degree of dissociation of acetic acid and hydrocyanic acid (HCN) in 1 M their respective solution of acids. ["Given "K_(a) (CH_(3)COOH)=1.8 xx 10^(-5) , K_(a(HCN))=6.2 xx 10^(-10)]

(a) Calculate the degree of dissociation of 0.0024 M acetic acid if conductivity of this solution is 8.0 xx 10^(-5)" S "cm^(-1) . Given . lambda_(H^(+))^(@) = 349.6" S " cm^(2)" mol"^(-1), lamda_(CH_(3)COO^(-))^(@)= 40.9" S " cm^(2) " mol "^(-1) (b) Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The limiting molar conductivity of ‘B’ increases to a smaller extent while that of ‘A’ increases to a much larger extent comparatively. Which of the two is a strong electrolyte? Justify your answer.

Amino acid glycine (NH_(2)-CH_(2)-COOH) exists as a zwitter ion in aq. Solution. The K_(a) and K_(b) values of glycine are 1.6xx10^(-10)(Pk_(a)=9.8) and 2.5xx10^(-12)(pk_(b)=11.6) respectively. The K_(a) and K_(b) values are for zwitter ion of Amino acid with following strctures [NH_(3)^(+)-CH_(2)-COO^(-)] An aqueous solution of glycine has pH: