How many grams of ice separated from solution prepared by mixing `2` mole urea in `1000gm` water, is frozen upto `-5^(@)C`. (Given: Kf for water is `1.86K.kg.mol^(-1)`)

When a solution w g of urea in 1 Kg of water is cooled to -0.372^(@)C,200g of ice is separated .If K_(f) for water is 1.86K Kgmol^(-1) ,w is

The amount of ice that will separate out from a solution containing 25 g of ethylene glycol in 100 g of water that is cooled to -10^(@)C , will be [Given : K_(f) "for" H_(2)O = 1.86K mol^(-1) kg ]

The amount of ice that will separate out from a solution containing 25 g of ethylene glycol in 100 g of water that is cooled to -10^(@)C , will be [Given : K_(f) "for" H_(2)O = 1.86K mol^(-1) kg ]

Calculate the amount of ice that will separate out on cooling containing 50 g of ethylene glycol in 200 g of water to -9.3^(@)C (K_(f) for water = 1.86 K mol^(-1) kg )

Calculate the amount of ice that will separate out on cooling containing 50 g of ethylene glycol in 200 g of water to -9.3^(@)C (K_(f) for water = 1.86 K mol^(-1) kg )

What do you understand by the term that K_(f) for water is 1.86 K kg mol^(-1) ?

Which of the following is/are true for a solution containing 30g urea in 100 g water? (K_(f) for water =1.9.^(@)C.kg//mol and K_(b) for water =0.5.^(@)Ckg//mol

Calculate the temperature at which a solution containing 54g of glucose, (C_(6)H_(12)O_(6)) in 250g of water will freeze. ( K_(f) for water = 1.86 K mol^(-1) kg)

1000gm of sucrose solution in water is cooled to -0.5^(@)C . How much of ice would be separated out at this temperature, if the solution started to freeze at -0.38^(@)C . Express your answer in gram. (K_(f)H_(2)O=1.86K "mol"^(-1)kg)

How many grams of methyl alcohol should be added to 10 litre tank of water to prevent its freezing at 268K ? (K_(f) for water is 1.86 K kg mol^(-1))