In a regular hexagon `ABCDEF`, if `bar (AB)=bar a`, `bar (BC)=bar b` then `bar (AD)=`

In a regular hexagon ABCDEF, bar(AB) + bar(AC)+bar(AD)+ bar(AE) + bar(AF)=k bar(AD) then k is equal to

ABCDE is a regular hexagon. i) If bar(AB) + bar(AE)+ bar(BC) + bar(DC) + bar(ED) + bar(AC)=lambdabar(AC) then lambda=

If ABCDEF is a regular hexagon , then bar(AB) + bar(AC) + bar(AE) + bar(AF) =

Let ABCDEF be a regular hexagon.If bar(AD)=xBC and bar(CF)=ybar(AB), then xy=a

If ABCDEF is a regular hexagon of side a, then bar(AB).bar(AF)=

If bar(a)+bar(b)+bar(c)=bar(0) then bar(a)timesbar(b)=

If ABCDEF is a regular hexagon, then bar(AC) + bar(AD) + bar(EA) + bar(FA) =

If PQRSTU is a regular hexagon such that bar(QR)+bar(QS)+bar(QP)+bar(QU)=alphabar(QT) , then : alpha=

If |bar(a)+bar(b)|<|bar(a)-bar(b)| then (bar(a),bar(b)) is