Speed of a particle moving in a circle varies with time as `V =2t`. If `a_t` is the tengential acceleration and `a_r` is the normal acceleration then

A particle is moving on a circle of radius A .At an instant its speed and tangential acceleration are B and C respectively.Total acceleration of the particle at that instant is

The speed of a particle moving in a circle of radius r=2m varies with time t as v=t^(2) , where t is in second and v in m//s . Find the radial, tangential and net acceleration at t=2s .

The speed of a particle moving in a circle of radius r=2m varies witht time t as v=t^(2) , where t is in second and v in m//s . Find the radial, tangential and net acceleration at t=2s .

The linear speed of a particle moving in a circle of radius R varies with time as v = v_0 - kt , where k is a positive constant. At what time the magnitudes of angular velocity and angular acceleration will be equal ?

Assertion:- A particle is moving in a circle with constant tangential acceleration such that its speed v is increasing. Angle made by resultant acceleration of the particle with tangential acceleration increases with time. Reason:- Tangential acceleration =|(dvecv)/(dt)| and centripetal acceleration =(v^(2))/(R)

For a particle moving along circular path, the radial acceleration a_x is proportional to time t. If a_t is the tangential acceleration, then which of the following will be independent of time t.

A point at the periphery of a disc rotating about a fixed axis moves so that its speed varies with time as v = 2 t^2 m//s The tangential acceleration of the point at t= 1s is

If a particle moves in a circle of radius 4m at speed given by v=2t at t=4 sec, Total Acceleration of the particle will be:

Tangental acceleration of a particle moving in a circle of radius 1 m varies with time t as shown in figure (initial velocity of the particle is zero). Time after which total acceleration of particle makes an angle of 30^(@) with radial acceleration is

A particle is moving along a circular path ofradius R in such a way that at any instant magnitude of radial acceleration & tangential acceleration are equal. 1f at t = 0 velocity of particle is V_(0) . Find the speed of the particle after time t=(R )//(2V_(0))