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If xy + yz +zx =0, then ((1)/(x ^(2) -...

If `xy + yz +zx =0,` then
`((1)/(x ^(2) - yz) + (1)/(y ^(2) - zx)+ (1)/( z ^(2) - xy))(x,y,z ne 0)` ie equal to:

A

3

B

0

C

1

D

`x+y+z`

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